Third Equation of Motion
Third Equation of Motion
THIRD EQUATION OF MOTION:
v= Final Velocity
u = Initial Velocity
a= Acceleration
s= Distance
Let us derive the third equation of motion
Distance travelled=average velocity X time
(I)
But from the first equation of motion, v = u + at
Substituting the value of t in Eq (I)
or
Example: A car is moving with an initial velocity of 5 m/s . The final velocity is 25 m/s when it accelerates at thr rate of 6 m/sq. s. Find the distance travelled
Sol: u = 5 m/s
v= 25 m/s
a = 6 m/sq. s
s = ?
(25+5)(25-50 = 12 s
30 X 20 = 12 s
600 = 12 s
The three equations listed can be used to solve the majority of kinematic problems.
A car, travelling at a speed of 20 km/hr is brought to rest by applying brakes. It covers a distance of 5 m before coming to rest. Had the speed of the car been 40 km/hr, find the distance it would have covered before coming to rest on applying the same force. | |||
| Right Option : C | |||
| View Explanation | |||
The speed of a car reduces from | |||
| Right Option : A | |||
| View Explanation | |||
The speed of a car reduces from | |||
| Right Option : A | |||
| View Explanation | |||
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